(x^2+4)/(x+2)=x-2

Solution for (x^2+4)/(x+2)=x-2 equation:

(x^2+4)/(x+2)=x-2

We move all terms to the left:

(x^2+4)/(x+2)-(x-2)=0


Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R


We get rid of parentheses

(x^2+4)/(x+2)-x+2=0

We multiply all the terms by the denominator


(x^2+4)-x*(x+2)+2*(x+2)=0

We multiply parentheses

-x^2+(x^2+4)-2x+2x+4=0

We get rid of parentheses

-x^2+x^2-2x+2x+4+4=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation